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1.4.13 Teaching examples: Example 5
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  Prove that the sequence is divergent.

  ProveBy contradiction : Suppose the given sequence converges to , that is

,

then it is defined by the limit . For , there exists such that when , there is always

,

using the basic absolute value inequality , that is, when , there is

,

the intervalThe length of is . And takes two numbers endlessly , and it is impossible to be at the same time, which is a contradiction. Therefore, the sequence is divergent .

  Note : This example also shows that bounded sequences do not necessarily converge.

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